MATH SOLVE

4 months ago

Q:
# Let f(x)=−14(x+4)2−8 .What is the average rate of change for the quadratic function from x=−2 to x = 2?

Accepted Solution

A:

Answer:

Average rate of change = -112

Explanation:

The average rate of change = [tex] \frac{f(b) - f(a)}{b - a} [/tex]

where:

b is the upper limit = 2

f(b) = f(2) = -14(2+4)² - 8 = -512

a is the lower limit = -2

f(a) = f(-2) = -14(-2+4)² - 8 = -64

Substitute with these values in the above equation to get the average rate of change as follows:

average rate of change = [tex] \frac{-512 - (-64)}{2 - (-2)} = -112[/tex]

Hope this helps :)

Average rate of change = -112

Explanation:

The average rate of change = [tex] \frac{f(b) - f(a)}{b - a} [/tex]

where:

b is the upper limit = 2

f(b) = f(2) = -14(2+4)² - 8 = -512

a is the lower limit = -2

f(a) = f(-2) = -14(-2+4)² - 8 = -64

Substitute with these values in the above equation to get the average rate of change as follows:

average rate of change = [tex] \frac{-512 - (-64)}{2 - (-2)} = -112[/tex]

Hope this helps :)