Q:

Graph the following lines and write the equation in slope-intercept form. d Through the point (2,βˆ’4) with y-intercept of βˆ’2.

Accepted Solution

A:
Check the picture below.[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-2})} \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{2}}}\implies \cfrac{-2+4}{-2}\implies \cfrac{2}{-2}\implies -1[/tex][tex]\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y+4=-x+2\implies y=-x-2[/tex]